Exactly!
As M31 moves with respect to Earth it really will take on a 1/R2
form. However, you might not be willing to stick around and take data for
the period of time necessary for you to see it!
Remember, the change in intensity of light is proportional to
![ratio of r to r+delta r](images/intensity-ratio.gif)
If the change in distance is very small compared to the initial distance,
this ratio is one, and the intensity will remain essentially unchanged.
Let's have another look at a 1/R2 graph light curve which is
intended to depict a person walking away from a wall while he or she
shines a flashlight on the wall. The graph represents the intensity of
the light on the wall as the person walks away. Let's suppose the time to
get to the midpoint on the graph is about 5 seconds.
Notice the graph now has a scale and the time to walk to the midpoint of
the graph (where the intensity is greatly reduced) is just 5 seconds.
Certainly over this timespan the effect of the light reduction and
therefore the curvature of the 1/R2 graph can be seen.
But lets now consider what must happen for this effect to be seen with
the intensity of M31. M31 is traveling very fast no doubt, but it has
been traveling fast for a very, very long time. When you begin to measure
the intensity of it from its lightcurve, which is certainly possible, it
is starting at an enourmous distance from the earth (and you the observer).
Even at a tremendous speed the galaxy covers a distance which is trivial
when compared to the distance it was from you alreadly. M31 is at a
distance of approximately 300,000 parsecs (pc) away from the earth.
And.... a parsec is approximately equal to 200,000 astronomical units (AU)
or in brief it is about 3 x 105 radii to the sun! Maybe to
make some sense of this we should look at the equations regarding this
again.
![Final Intensity = Initial Intensity/(r + delta r)squared](images/intensity_eq_1.gif)
The final intensity proportional to the initial intensity and inversely
proportional to the distance to M31 squared. But what happens to the
equation when Dr is very, very small as compared
to r? Here's a little spreadsheet which shows the results.
![Spreadsheet showing Intensity Final for Increasing Delta r](images/intensity_spreadsheet.gif)
So...now you know why the light curve for M31 looks flat!
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